Optimal. Leaf size=136 \[ -\frac{1}{2} a^2 \text{PolyLog}\left (2,-\frac{\sqrt{1-a x}}{\sqrt{a x+1}}\right )+\frac{1}{2} a^2 \text{PolyLog}\left (2,\frac{\sqrt{1-a x}}{\sqrt{a x+1}}\right )-\frac{a \sqrt{1-a^2 x^2}}{2 x}-\frac{\sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{2 x^2}+a^2 \tanh ^{-1}(a x) \tanh ^{-1}\left (\frac{\sqrt{1-a x}}{\sqrt{a x+1}}\right ) \]
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Rubi [A] time = 0.198167, antiderivative size = 136, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {6010, 6026, 264, 6018} \[ -\frac{1}{2} a^2 \text{PolyLog}\left (2,-\frac{\sqrt{1-a x}}{\sqrt{a x+1}}\right )+\frac{1}{2} a^2 \text{PolyLog}\left (2,\frac{\sqrt{1-a x}}{\sqrt{a x+1}}\right )-\frac{a \sqrt{1-a^2 x^2}}{2 x}-\frac{\sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{2 x^2}+a^2 \tanh ^{-1}(a x) \tanh ^{-1}\left (\frac{\sqrt{1-a x}}{\sqrt{a x+1}}\right ) \]
Antiderivative was successfully verified.
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Rule 6010
Rule 6026
Rule 264
Rule 6018
Rubi steps
\begin{align*} \int \frac{\sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{x^3} \, dx &=-\frac{\sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{x^2}+a \int \frac{1}{x^2 \sqrt{1-a^2 x^2}} \, dx-\int \frac{\tanh ^{-1}(a x)}{x^3 \sqrt{1-a^2 x^2}} \, dx\\ &=-\frac{a \sqrt{1-a^2 x^2}}{x}-\frac{\sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{2 x^2}-\frac{1}{2} a \int \frac{1}{x^2 \sqrt{1-a^2 x^2}} \, dx-\frac{1}{2} a^2 \int \frac{\tanh ^{-1}(a x)}{x \sqrt{1-a^2 x^2}} \, dx\\ &=-\frac{a \sqrt{1-a^2 x^2}}{2 x}-\frac{\sqrt{1-a^2 x^2} \tanh ^{-1}(a x)}{2 x^2}+a^2 \tanh ^{-1}(a x) \tanh ^{-1}\left (\frac{\sqrt{1-a x}}{\sqrt{1+a x}}\right )-\frac{1}{2} a^2 \text{Li}_2\left (-\frac{\sqrt{1-a x}}{\sqrt{1+a x}}\right )+\frac{1}{2} a^2 \text{Li}_2\left (\frac{\sqrt{1-a x}}{\sqrt{1+a x}}\right )\\ \end{align*}
Mathematica [A] time = 0.662267, size = 126, normalized size = 0.93 \[ \frac{1}{8} a^2 \left (-4 \text{PolyLog}\left (2,-e^{-\tanh ^{-1}(a x)}\right )+4 \text{PolyLog}\left (2,e^{-\tanh ^{-1}(a x)}\right )+2 \tanh \left (\frac{1}{2} \tanh ^{-1}(a x)\right )-4 \tanh ^{-1}(a x) \log \left (1-e^{-\tanh ^{-1}(a x)}\right )+4 \tanh ^{-1}(a x) \log \left (e^{-\tanh ^{-1}(a x)}+1\right )-2 \coth \left (\frac{1}{2} \tanh ^{-1}(a x)\right )-\tanh ^{-1}(a x) \text{csch}^2\left (\frac{1}{2} \tanh ^{-1}(a x)\right )-\tanh ^{-1}(a x) \text{sech}^2\left (\frac{1}{2} \tanh ^{-1}(a x)\right )\right ) \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.256, size = 141, normalized size = 1. \begin{align*} -{\frac{ax+{\it Artanh} \left ( ax \right ) }{2\,{x}^{2}}\sqrt{- \left ( ax-1 \right ) \left ( ax+1 \right ) }}+{\frac{{a}^{2}{\it Artanh} \left ( ax \right ) }{2}\ln \left ( 1+{(ax+1){\frac{1}{\sqrt{-{a}^{2}{x}^{2}+1}}}} \right ) }+{\frac{{a}^{2}}{2}{\it polylog} \left ( 2,-{(ax+1){\frac{1}{\sqrt{-{a}^{2}{x}^{2}+1}}}} \right ) }-{\frac{{a}^{2}{\it Artanh} \left ( ax \right ) }{2}\ln \left ( 1-{(ax+1){\frac{1}{\sqrt{-{a}^{2}{x}^{2}+1}}}} \right ) }-{\frac{{a}^{2}}{2}{\it polylog} \left ( 2,{(ax+1){\frac{1}{\sqrt{-{a}^{2}{x}^{2}+1}}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{-a^{2} x^{2} + 1} \operatorname{artanh}\left (a x\right )}{x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{-a^{2} x^{2} + 1} \operatorname{artanh}\left (a x\right )}{x^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{- \left (a x - 1\right ) \left (a x + 1\right )} \operatorname{atanh}{\left (a x \right )}}{x^{3}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{-a^{2} x^{2} + 1} \operatorname{artanh}\left (a x\right )}{x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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